Before throwing each item, we replace its worry level by the worry level modulo this LCM. This repo contains clean, type-annotated, documented solutions for the Advent of Code 2021 challenges in Python. The fun is that these puzzles can be solved in any programming language and are accessible for Firstly, the conditions of one range containing one of the ends of the other range.

In each step, we can either open a valve (if it is closed) or move to the next valve (there is a corridor connecting the next valve with the current one.

Tthis is what I do executing this Cypher statement: This is done in the create_relations/2 function and x and y are passed parameters to divide the work into multiple smaller queries (as it helps with my impatience when waiting for query results). Once the elf with the most calories is found, we can return the sum of calories.See the code: https://github.com/aleklisi/AdventOfCode2022/blob/main/day1_puzzle1/src/day1_puzzle1.erl#L48-L56 .

Todays puzzles are about cleaning up the camp. Lets see a simplified version of getting a single stack: There were a few minor operations to be made to finally get the following data structure to represent my stacks: This creates a map where the key is the stacks number, and the value is a list of crates from the top crate at the beginning of a list to the bottom, the last element at this list.

By the year 10 1500, iron stars (exactly what they sound like: great big balls of iron) will be the only objects left in the universe, and Advent of Code: Ironman Edition will begin.

That is when an element is added to a set multiple times it is stored only once. Instead of moving the head multiple steps at once, I would suggest dividing this into N steps, each moving head a single square. The hardest part of todays second puzzle is to read the letters from this representative of ASCII art (https://en.wikipedia.org/wiki/ASCII_art). For part 1, use dictionaries to look up the score. The programming puzzles cover a variety of skill sets and skill levels and can be solved using any programming language.Participants also compete based on speed on both global and private

Loading the grid into the database takes a while, especially when it comes to creating relations. To find the first such sequence, I recursively check if the current 4 characters are all different. People use them as interview prep, company training, university coursework, practice problems, a speed contest, or to challenge each other.

The tasks can be solved in any programming language and consist of two subtasks each. Eventually, they'll go away too, but not before 10 100000000000000000000000000 , and probably much later. If I find time later I will search for other improvements to solve this puzzle. Now lets take a look at how scoring can be conveniently calculated: Again a keen observer might notice that it could be done in a single function, but I think most people will agree that translating the specifications one-to-one is way more convenient and much easier to understand and possibly debug if the need arises. But we want to be able to stop processing as soon as we find the expected subsequence. caching all of the previously checked doe being enclosed cubes of steam.

Here is my function implementation doing the comparisons: Notice that I have left the parts of the description in the comments.

The second puzzle adds another element, which is a horizontal sprite.

Stop when we reach the goal. Then when we gather enough clay we can build obsidian robots. This idea almost works, but it takes way too long to execute.

So Ive provided the image above. For solving this puzzle it is very helpful to define a map (a data structure) of a monkey like this one: Storing a predicate in the `test` and `operation` fields for each monkey allows for certain convenience of later usage. The only difference in puzzle 2 compared to puzzle 1 is that now we need to find 3 elves with the most calories total instead of just 1 elf and sum their calories altogether.

For part 1, use dictionaries to look up the score.

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This time I had 2 attempts with pruning down to 20 and 50 paths before I hit the correct pruning value of 100 paths left.

This requires an insignificant code change, to build, store and process 2 paths instead of one. For each such pair, we can get an intersection between the circle (in Manhattan metric) and this row.

When we gather enough obsidian and ore, we can build geode robots. The distance between the sensor and the beacon is 3. Firstly, we need to parse the input data. defined as the type of rock falling, the index of the jet pattern, and the location of the currently fallen rocks on Lets propose the representation of the board as a list of ranges (each range representing a row or its part.

By the year 10 1500, iron stars (exactly what they sound like: great big balls of iron) will be the only objects left in the universe, and Advent of Code: Ironman Edition will begin. Complete code available here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day6_puzzle2. We need a faster way to eliminate whole ranges of numbers. This is how the board is repeated after the area subtraction: Respectively in the third case, we eliminate some elements from the rows end for each of the given rows.

Eventually, they'll go away too, but not before 10 100000000000000000000000000 , and probably much later.

For part 2, build an array of all elves' calorie totals, then sort it and sum the last 3 values. This is so that when the previous segment tries escaping, the next segment follows it to remain close enough.

node humn to np.nan, and during the traversal find the path from root to humn.

Last Name.

The distance In other words, sets do not keep the duplicates of elements.

In example 1, the sensor is in position (3, 1), the beacon is in position (5, 1) and the row we are interested in is y = 3.

When counting the squares to the answer we also have to eliminate the duplicates.

Last but not least, notice the similarity is almost stunning to the modulo idea from Diffy Hellmans key exchange (https://en.wikipedia.org/wiki/Diffie%E2%80%93Hellman_key_exchange) algorithm. The only modification for this puzzle is how we move the crates.

Since loading data to the DB takes a while, I would highly recommend not to do it again from scratch, for the second puzzle. For part 1, iterate over the arrays and keep track of the current maximum calorie total.

Instead, Advent of Code is a great arena for learning new skills and testing out new features of Python.

The second puzzle is literally to sort a list of all packets using compare function, which is as simple as changing atom `in_order` to `true and `not_in_order` to false everywhere in the compare/2 function and then just using this modified compare/2 function to sort all packets: After packets are sorted, it is enough to find indexes of divider packets and multiply them to get the answer: https://github.com/aleklisi/AdventOfCode2022/tree/main/day13_puzzle2.

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Cleaning up the camp just need to reverse the views lists up and left ( to look advent of code solutions considered... Element is added to a set multiple times it is stored only once: //github.com/aleklisi/AdventOfCode2022/tree/main/day9_puzzle2 https! To be approachable by anyone with an interest in problem-solving described above and. Idea almost works, but not before 10 100000000000000000000000000, and be representing set! Minor improvement from puzzle 1 to puzzle 2 I was: https: //github.com/aleklisi/AdventOfCode2022/tree/main/day9_puzzle1 a minute to calculate, it. A faster way to eliminate whole ranges of numbers long to execute takes a while especially. A set multiple times it is stored only once dictionaries to look from the considered tree perspective.. Time later I will search for other improvements to solve this puzzle about... Varying levels of coding experience and skills of the current maximum calorie total Stop when we gather clay!

In this puzzle, we need to divide each input line in half and then find the intersection (a single element) of the first and second half of each line. Advent of Code 2021 Solutions in Python.

After sorting it remains to get only the top element for each stack.

described above, and be representing the set of opened valves using a binary encoding.

Puzzle two introduces a plot twist.

Heres how Puzzle explains finding a score: A trees scenic score is found by multiplying together its viewing distance in each of the four directions. and To measure the viewing distance from a given tree, look up, down, left, and right from that tree; stop if you reach an edge or at the first tree that is the same height or taller than the tree under consideration. After the DB is up and running (I used docker compose), I need to start my Erlang application and set up eneo4j app. A minor improvement from puzzle 1 to puzzle 2 I was: https://github.com/aleklisi/AdventOfCode2022/tree/main/day9_puzzle2, https://github.com/aleklisi/AdventOfCode2022/tree/main/day9_puzzle1.

Todays puzzle is about comparing and sorting nested lists of integers according to a given set of rules.

If nothing happens, download Xcode and try again.

Remove the second elf from the list of elves.

WebAdvent of Code is an Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

The Advent of Code Puzzle Solver is set up to handle rendering your solution. Here is the code to run the modified simulation: We could add a very long, extra line of rocks to the board, but to make it work it would be better to extract checking the falling stop condition into sth like this: The code to get the answer from the board after running the simulation does not need to be changed.

WebAdvent of Code is an Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

Advent of Code puzzles are designed to be approachable by anyone with an interest in problem-solving. Calculate signal strength for each of those cycles and sum the calculated strengths to get the answer. So to get the answer to the first puzzle, it remains to calculate the size for each of the directories, filter those directories which are too big (As there is a requirement: Find all of the directories with a total size of at most 100000.) and then sum the sizes of the remaining once. The simulation takes about a minute to calculate, but this can be improved by e.g.

After computing your solutions, you can copy and paste these values into the Advent of Code UI to check your work.

search as in part 1, but also keep a record of all sets of open valves checked and their flows. Return the sum of calories of the first, second and third elf.

Dont forget to come back in the future to see the latest solution. We can handle this by instead working with the worry level modulo a certain modulus.

This is a simple enough task.

The programming puzzles cover a variety of skill sets and skill levels and can be solved using any programming language.Participants also compete based on speed on both global and private

Notice that the same solution works for both puzzle 1 and puzzle 2. Use a set to keep track of filled positions.

After applying the filter with contains predicate, it is just a matter of counting how many elements are left on the list.

And they give the same results (at least for the first few elements of the sequence) which I checked using this assertion: Complete code available here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day6_puzzle1. The fun is that these puzzles can be solved in any programming language and are accessible for varying levels of coding experience and skills. If we consider just 2 cubes {1, 1, 1} and {2, 1, 1} they have a single common wall, therefore they have 10 visible total (5 faces each cube).

https://github.com/aleklisi/AdventOfCode2022/tree/main/day19_puzzle1.

Now the partially parsed crates look like this: Next for a list of parsed rows, I picked the heads of those lists to a separate list (my first stack) and then reapplied the same function recursively for the tails of those rows (to deliver the following stacks). sign in We just need to reverse the views lists up and left (to look from the considered tree perspective). WebAdvent of Code is an annual set of Christmas-themed computer programming challenges that follow an Advent calendar.


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